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vector<ll> kthperm(ll n, ll k) {
Tree<ll> t;
vector<ll> res(n);
for (ll i = 1; i <= n; k /= i, i++) {
t.insert(i - 1);
res[n - i] = k % i;
}
for (ll& x : res) {
auto it = t.find_by_order(x);
x = *it;
t.erase(it);
}
return res;
}
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