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// Laufzeit: O(n*log(n))
ll merge(vector<ll>& v, vector<ll>& left, vector<ll>& right) {
int a = 0, b = 0, i = 0;
ll inv = 0;
while (a < ssize(left) && b < ssize(right)) {
if (left[a] < right[b]) v[i++] = left[a++];
else {
inv += ssize(left) - a;
v[i++] = right[b++];
}
}
while (a < ssize(left)) v[i++] = left[a++];
while (b < ssize(right)) v[i++] = right[b++];
return inv;
}
ll mergeSort(vector<ll> &v) { // Sortiert v und gibt Inversionszahl zurück.
int n = ssize(v);
vector<ll> left(n / 2), right((n + 1) / 2);
for (int i = 0; i < n / 2; i++) left[i] = v[i];
for (int i = n / 2; i < n; i++) right[i - n / 2] = v[i];
ll result = 0;
if (ssize(left) > 1) result += mergeSort(left);
if (ssize(right) > 1) result += mergeSort(right);
return result + merge(v, left, right);
}
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