diff options
| author | mzuenni <michi.zuendorf@gmail.com> | 2022-06-27 17:19:28 +0200 |
|---|---|---|
| committer | mzuenni <michi.zuendorf@gmail.com> | 2022-06-27 17:19:28 +0200 |
| commit | 5ab8a5088b729a9953b8dff1b2a985dc8fb2098b (patch) | |
| tree | ed40d6936c0e9eee40ba62751cbf99ecddbaddc2 /graph/TSP.cpp | |
| parent | adabbad9c51cf7cd3874bfde8eac1fbcf84fec10 (diff) | |
updated tcr
Diffstat (limited to 'graph/TSP.cpp')
| -rw-r--r-- | graph/TSP.cpp | 41 |
1 files changed, 23 insertions, 18 deletions
diff --git a/graph/TSP.cpp b/graph/TSP.cpp index 7fba361..0f72766 100644 --- a/graph/TSP.cpp +++ b/graph/TSP.cpp @@ -1,23 +1,28 @@ -// Laufzeit: O(n^2*2^n) -vector<vector<int>> dist; // Entfernung zwischen je zwei Punkten. -vector<int> TSP() { - int n = dist.size(), m = 1 << n; - vector<vector<ii>> dp(n, vector<ii>(m, ii(INF, -1))); +vector<vector<ll>> dist; // Entfernung zwischen je zwei Punkten. + +void TSP() { + int n = sz(dist), m = 1 << n; + vector<vector<edge>> dp(n, vector<edge>(m, edge{INF, -1})); - for(int c = 0; c < n; c++) dp[c][m-1].first = dist[c][0], dp[c][m-1].second = 0; + for (int c = 0; c < n; c++) + dp[c][m-1].dist = dist[c][0], dp[c][m-1].to = 0; - for(int v = m - 2; v >= 0; v--) { - for(int c = n - 1; c >= 0; c--) { - for(int g = 0; g < n; g++) { - if(g != c && !((1 << g) & v)) { - if((dp[g][(v | (1 << g))].first + dist[c][g]) < dp[c][v].first) { - dp[c][v].first = dp[g][(v | (1 << g))].first + dist[c][g]; - dp[c][v].second = g; + for (int v = m - 2; v >= 0; v--) { + for (int c = n - 1; c >= 0; c--) { + for (int g = 0; g < n; g++) { + if (g != c && !((1 << g) & v)) { + if ((dp[g][(v | (1 << g))].dist + dist[c][g]) < + dp[c][v].dist) { + dp[c][v].dist = + dp[g][(v | (1 << g))].dist + dist[c][g]; + dp[c][v].to = g; }}}}} + // return dp[0][1]; // Länge der Tour - vector<int> res; res.push_back(0); int v = 0; - while(res.back() != 0 || res.size() == 1) { - res.push_back(dp[res.back()][(v |= (1 << res.back()))].second); - } - return res; // Enthält Knoten 0 zweimal. An erster und letzter Position. + vector<int> tour; tour.push_back(0); int v = 0; + while (tour.back() != 0 || sz(tour) == 1) + tour.push_back(dp[tour.back()] + [(v |= (1 << tour.back()))].to); + // Enthält Knoten 0 zweimal. An erster und letzter Position. + // return tour; } |
