diff options
Diffstat (limited to 'content')
| -rw-r--r-- | content/datastructures/datastructures.tex | 2 | ||||
| -rw-r--r-- | content/datastructures/unionFind.cpp | 4 | ||||
| -rw-r--r-- | content/graph/binary_lifting.cpp | 2 | ||||
| -rw-r--r-- | content/graph/graph.tex | 6 | ||||
| -rw-r--r-- | content/math/math.tex | 2 | ||||
| -rw-r--r-- | content/math/tables/stuff.tex | 2 | ||||
| -rw-r--r-- | content/math/transforms/andTransform.cpp | 4 | ||||
| -rw-r--r-- | content/math/transforms/bitwiseTransforms.cpp | 6 | ||||
| -rw-r--r-- | content/math/transforms/orTransform.cpp | 4 | ||||
| -rw-r--r-- | content/math/transforms/xorTransform.cpp | 2 |
10 files changed, 17 insertions, 17 deletions
diff --git a/content/datastructures/datastructures.tex b/content/datastructures/datastructures.tex index 1c51475..38d63d9 100644 --- a/content/datastructures/datastructures.tex +++ b/content/datastructures/datastructures.tex @@ -78,7 +78,7 @@ \sourcecode{datastructures/bitset.cpp} \end{algorithm} -\begin{algorithm}{Link-Cut-Tree} +\begin{algorithm}{Link/Cut Tree} \begin{methods} \method{LCT}{baut Wald auf}{n} \method{connected}{prüft ob zwei Knoten im selben Baum liegen}{\log(n)} diff --git a/content/datastructures/unionFind.cpp b/content/datastructures/unionFind.cpp index 36a4b45..8861790 100644 --- a/content/datastructures/unionFind.cpp +++ b/content/datastructures/unionFind.cpp @@ -15,11 +15,11 @@ struct UnionFind { return true; } - int size(int a) { + int size(int a) { // optional return -unions[find(a)]; } - int add() { + int add() { // optional unions.push_back(-1); return ssize(unions) - 1; } diff --git a/content/graph/binary_lifting.cpp b/content/graph/binary_lifting.cpp index f88b1a9..5ed6c07 100644 --- a/content/graph/binary_lifting.cpp +++ b/content/graph/binary_lifting.cpp @@ -3,7 +3,7 @@ struct Lift { Lift(vector<vector<int>> &adj, int root): dep(adj.size()), par(adj.size()), jmp(adj.size(), root) { - auto dfs = [&](auto &self, int u, int p, int d) -> void { + auto dfs = [&](auto &&self, int u, int p, int d) -> void { dep[u] = d, par[u] = p; jmp[u] = dep[p] + dep[jmp[jmp[p]]] == 2*dep[jmp[p]] ? jmp[jmp[p]] : p; diff --git a/content/graph/graph.tex b/content/graph/graph.tex index bf51d74..f6f3d02 100644 --- a/content/graph/graph.tex +++ b/content/graph/graph.tex @@ -118,7 +118,7 @@ \subsubsection{\textsc{Floyd-Warshall}-Algorithmus} \method{floydWarshall}{kürzeste Pfade oder negative Kreise finden}{\abs{V}^3} \begin{itemize} - \item \code{dist[i][i] = 0, dist[i][j] = edge\{j, j\}.weight} oder \code{INF} + \item \code{dist[i][i] = 0, dist[i][j] = edge\{i, j\}.weight} oder \code{INF} \item \code{i} liegt auf einem negativen Kreis $\Leftrightarrow$ \code{dist[i][i] < 0}. \end{itemize} \sourcecode{graph/floydWarshall.cpp} @@ -140,12 +140,12 @@ Sei $a_{ij}$ die Adjazenzmatrix von $G$ \textcolor{gray}{(mit $a_{ii} = 1$)}, da \begin{algorithm}{Dynamic Connectivity} \begin{methods} \method{Constructor}{erzeugt Baum ($n$ Knoten, $m$ updates)}{n+m} - \method{addEdge}{fügt Kannte ein,\code{id}=delete Zeitpunkt}{\log(n)} + \method{addEdge}{fügt Kante ein, \code{id} = delete-Zeitpunkt}{\log(n)} \method{eraseEdge}{entfernt Kante \code{id}}{\log(n)} \end{methods} \sourcecode{graph/connect.cpp} \end{algorithm} -\clearpage +\columnbreak diff --git a/content/math/math.tex b/content/math/math.tex index 7764d54..5899c97 100644 --- a/content/math/math.tex +++ b/content/math/math.tex @@ -7,7 +7,7 @@ \end{itemize}
\sourcecode{math/longestIncreasingSubsequence.cpp}
\end{algorithm}
-\vfill\null\columnbreak
+\columnbreak
\begin{algorithm}{Zykel Erkennung}
\begin{methods}
diff --git a/content/math/tables/stuff.tex b/content/math/tables/stuff.tex index 82f2d3f..9ad4739 100644 --- a/content/math/tables/stuff.tex +++ b/content/math/tables/stuff.tex @@ -3,7 +3,7 @@ \hline \multicolumn{2}{|c|}{Verschiedenes} \\ \hline - Türme von Hanoi, minimale Schirttzahl: & + Türme von Hanoi, minimale Schrittzahl: & $T_n = 2^n - 1$ \\ \#Regionen zwischen $n$ Geraden & diff --git a/content/math/transforms/andTransform.cpp b/content/math/transforms/andTransform.cpp index 9e40c74..87bae0b 100644 --- a/content/math/transforms/andTransform.cpp +++ b/content/math/transforms/andTransform.cpp @@ -3,6 +3,6 @@ void fft(vector<ll>& a, bool inv = false) { for (int s = 1; s < n; s *= 2) { for (int i = 0; i < n; i += 2 * s) { for (int j = i; j < i + s; j++) { - ll& u = a[j], &v = a[j + s]; - tie(u, v) = inv ? pair(u - v, v) : pair(u + v, v); + ll &u = a[j], &v = a[j + s]; + u = inv ? u - v : u + v; }}}} diff --git a/content/math/transforms/bitwiseTransforms.cpp b/content/math/transforms/bitwiseTransforms.cpp index 17f3163..c0f6e50 100644 --- a/content/math/transforms/bitwiseTransforms.cpp +++ b/content/math/transforms/bitwiseTransforms.cpp @@ -3,9 +3,9 @@ void bitwiseConv(vector<ll>& a, bool inv = false) { for (int s = 1; s < n; s *= 2) { for (int i = 0; i < n; i += 2 * s) { for (int j = i; j < i + s; j++) { - ll& u = a[j], &v = a[j + s]; - tie(u, v) = inv ? pair(u - v, v) : pair(u + v, v); // AND - //tie(u, v) = inv ? pair(u, v - u) : pair(u, v + u); //OR + ll &u = a[j], &v = a[j + s]; + u = inv ? u - v : u + v; // AND + //v = inv ? v - u : v + u; // OR //tie(u, v) = pair(u + v, u - v); // XOR }}} //if (inv) for (ll& x : a) x /= n; // XOR (careful with MOD) diff --git a/content/math/transforms/orTransform.cpp b/content/math/transforms/orTransform.cpp index 6503a68..1833ac5 100644 --- a/content/math/transforms/orTransform.cpp +++ b/content/math/transforms/orTransform.cpp @@ -3,6 +3,6 @@ void fft(vector<ll>& a, bool inv = false) { for (int s = 1; s < n; s *= 2) { for (int i = 0; i < n; i += 2 * s) { for (int j = i; j < i + s; j++) { - ll& u = a[j], &v = a[j + s]; - tie(u, v) = inv ? pair(u, v - u) : pair(u, v + u); + ll &u = a[j], &v = a[j + s]; + v = inv ? v - u : v + u; }}}} diff --git a/content/math/transforms/xorTransform.cpp b/content/math/transforms/xorTransform.cpp index 075aac3..aa3db8d 100644 --- a/content/math/transforms/xorTransform.cpp +++ b/content/math/transforms/xorTransform.cpp @@ -3,7 +3,7 @@ void fft(vector<ll>& a, bool inv = false) { for (int s = 1; s < n; s *= 2) { for (int i = 0; i < n; i += 2 * s) { for (int j = i; j < i + s; j++) { - ll& u = a[j], &v = a[j + s]; + ll &u = a[j], &v = a[j + s]; tie(u, v) = pair(u + v, u - v); }}} if (inv) for (ll& x : a) x /= n; |